How do you find the unit vector having the same direction as vector v = 2i - j + k?

1 Answer
Jul 13, 2016

The unit vector having the same direction as #v# will be #2/sqrt6i-1/sqrt6j+1/sqrt6k#

Explanation:

For a vector #v=ai+bj+ck#, unit vector in the same direction is given by #v/(|v|)#, where #|v|=sqrt(a^2+b^2+c^2)#.

Hence for #v=2i-j+k#, as #|v|=sqrt(2^2+(-1)^2+1^2)#

= #sqrt(4+1+1)=sqrt6#

Hence. the unit vector having the same direction as #v# will be

#2/sqrt6i-1/sqrt6j+1/sqrt6k#