How do you find the vertex and the intercepts for #y=x^2 - 8x + 3#?
1 Answer
Jul 14, 2016
Vertex (4, -13)
Explanation:
x-coordinate of vertex:
y-coordinate of vertex:
y(4) = 16 - 32 + 3 = -13
Vertex (4, -13)
To find y-intercepts, make x = 0 --> y = 3
To find x-intercepts, solve the quadratic equation y = 0
Use the improved quadratic formula (Google Search)
There are 2 x-intercepts (2 real roots):
graph{x^2 - 8x + 3 [-40, 40, -20, 20]}