Question

How do you evaluate `sin^-1(sin((7pi)/6))`?

Answer 1

#(7pi)/6

Explanation:

The answer follows from the definition of the inverse `f^(-1)`of a

function f:

If `y = f(x) , x = f^(-1)(y), f^(-1)f(x)=x and ff^(-1)(y) = y`

Here, `f =sin and x = (7pi)/6`.