How do you find the x and y intercepts for #f(x)=2(x-5)^2 -50#?

1 Answer
Jul 17, 2016

Intercepts on #x#-axis are #0# and #10#; intercept on #y#-axis is #0#.

Explanation:

In the function #f(x)=2(x-5)^2-50#, #x#-intercept is given by #f(x)=0# and #y#-intercept is given by #f(0)#.

As such #x#-intercept is given by #2(x-5)^2-50=0# i.e. #2(x^2-10x+25)-50=0# or

#2x^2-20x=0# or #2x(x-10)=0# i.e. #x=0# and #x=10#.

#y#-intercept is #f(0)=2(0-5)^2-50=2*25-50=0#.

Hence while intercepts on #x#-axis are #0# and #10#; intercept on #y#-axis is #0#.