A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is $\frac{5 π}{24}$ $(5pi)/24$ and the angle between B and C is $\frac{3 π}{8}$ $(3pi)/8$ . What is the area of the triangle?

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A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is $\frac{5 π}{24}$ $(5pi)/24$ and the angle between B and C is $\frac{3 π}{8}$ $(3pi)/8$ . What is the area of the triangle?

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Answer 1 · 2016-07-20T04:34:13

$2.9 s q u n i t$ $2.9squnit$

Explanation:

Given

$A, B, C are three sides of a triangle$ $A,B,C " are three sides of a triangle"$

$A = 2 and B = 3$ $A=2 and B =3$

$Angle between A & C = (\frac{5 π}{24})$ $"Angle between A & C"=((5pi)/24)$

$Angle between B & C = (\frac{3 π}{8})$ $"Angle between B & C"=((3pi)/8)$

$Let Angle between A & B = θ$ $"Let Angle between A & B"=theta$
$= π - \frac{3 π}{8} - \frac{5 π}{24} = \frac{(24 - 9 - 5) π}{24} = \frac{5 π}{12}$ $=pi-(3pi)/8-(5pi)/24=((24-9-5)pi)/24=(5pi)/12$

$Area of triangle = \frac{1}{2} \cdot A \cdot B \cdot sin θ$ $"Area of triangle"=1/2*A*B*sintheta$

$= \frac{1}{2} \cdot 2 \cdot 3 \cdot sin (\frac{5 π}{12}) = 2.9 s q u n i t$ $=1/2*2*3*sin((5pi)/12)=2.9squnit$

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A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is $\frac{5 π}{24}$ $(5pi)/24$ and the angle between B and C is $\frac{3 π}{8}$ $(3pi)/8$ . What is the area of the triangle?

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Explanation:

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Science

Math

Humanities

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A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is 5π24(5pi)/24 and the angle between B and C is 3π8 (3pi)/8. What is the area of the triangle?

1 Answer

Explanation:

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A triangle has sides A, B, and C. Sides A and B have lengths of 2 and 3, respectively. The angle between A and C is $\frac{5 π}{24}$ $(5pi)/24$ and the angle between B and C is $\frac{3 π}{8}$ $(3pi)/8$ . What is the area of the triangle?