How do you write # y=-2(x+1)^2 +3# in standard form?

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Answer 1 · 2016-07-28T11:41:14

#y=-2x^2-4x+1#

Consider #" "(x+1)^2#

Write as:#" "color(blue)((x+1))color(brown)((x+1))#

Multiply everything inside the right hand side bracket by everything inside the left hand bracket.

#color(brown)(color(blue)(x)(x+1)color(blue)( +1)(x+1))#

#x^2+x" "+x+1" "->" "x^2+2x+1#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#=>color(brown)(y=-2(x+1)^2+3)color(green)(" "->" "y=-2(x^2+2x+1)+3)#

#=>y=-2x^2-4x-2+3#

#=>y=-2x^2-4x+1#