Question

What is the vertex form of `y=x^2 + 3x - 10`?

Answer 1

In Vertex form: `y=(x+3/2)^2- 49/4`

Explanation:

`y=x^2+3x-10 = (x+3/2)^2-9/4-10=(x+3/2)^2- 49/4` Comparing with general vertex form `y=a(x-h)^2+k` we get vertex is at `(h,k)or (-3/2,-49/4)` graph{x^2+3x-10 [-40, 40, -20, 20]}[Ans]