How do you multiply # (4r - 3)(3r - 2)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Shwetank Mauria Aug 2, 2016 #(4r-3)(3r-2)=12r^2-17r+6# Explanation: #(4r-3)(3r-2)# = #4r(3r-2)-3(3r-2)# = #12r^2-8r-9r+6# = #12r^2-17r+6# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1337 views around the world You can reuse this answer Creative Commons License