Question

What are the components of the vector between the origin and the polar coordinate `(1, (3pi)/8)`?

Answer 1

If `(r,theta)` be the polar coordinate of point then the position vector of the point is

`veca=rcosthetahati+rsinthetahatj`

`"For "r=1 and theta =(3pi)/8" "veca" becomes`

`veca=1*cos(3pi/8)i+1*sin(3pi/8)j`

`veca=(0.38)i+(0.92)j`