What is the distance between #(5, –6, 4) # and #(4, –1, 2)#?

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Answer 1 · 2016-08-03T08:47:19

The distance between #(5,-6,4)# and #(4,-1,2)# is #5.477#

The distance between two points whose coordinates are #(x_1,y_1,z_1)# and #(x_2,y_2,z_2)# is given by

#sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)#

Hence, the distance between #(5,-6,4)# and #(4,-1,2)# is

#sqrt((4-5)^2+((-1)-(-6))^2+(2-4)^2)#

= #sqrt((-1)^2+(-1+6)^2+(-2)^2)#

= #sqrt(1+5^2+4)#

= #sqrt(1+25+4)=sqrt30=5.477#