How much water must be added to 12 L (liters) of a 40% solution of alcohol to obtain a 30% solution?
1 Answer
Aug 6, 2016
4 L.
Explanation:
Alcohol in 40% solution = 12 X 0.4 = 4.8 L.
If w L water is to be added for 30% solution,
( 12 + w ) X 0.3 = 4.8
So, w = (4.8-3.6)/0.3= 4 L..
