Question

To what volume should you dilute 20 mL of a 12 M `H_2SO_4` solution to obtain a 0.16 M `H_2SO_4` solution?

Answer 1

`C_1V_1=C_2V_2`.

A final volume of `1.500*L` is required.

Explanation:

The product `C_1V_1` is by definition the number of moles of stuff, which is fixed according to the volume and the concentration of your starting material.

We started with `20*mL` of `12*mol*L^-1` `"sulfuric acid"`.

And thus `(20*mLxx12*cancel(mol*L^-1))/(0.16*cancel(mol*L^-1))=V_2=1500*mL`

PS When you do the dilution, do you add the acid to the water? Why?