How do you simplify #root5(32x^5)#?

Question

2402 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-15T09:42:45

2x

its the same as #(2^5x^5)^(1/5 )= 2x#

Answer 2 · 2016-08-15T09:44:00

#2x#

Write 32 as the product of its prime factors..

#root5(2xx2xx2xx2xx2xx x^5)#

=#root5(2^5x^5)" divide the index by the root"#

=#2x#