How do you simplify #root5(32x^5)#? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 2 Answers Rory K. · EZ as pi Aug 15, 2016 2x Explanation: its the same as #(2^5x^5)^(1/5 )= 2x# Answer link EZ as pi Aug 15, 2016 #2x# Explanation: Write 32 as the product of its prime factors.. #root5(2xx2xx2xx2xx2xx x^5)# =#root5(2^5x^5)" divide the index by the root"# =#2x# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 2350 views around the world You can reuse this answer Creative Commons License