What is the vertex form of #y=2x^2+8x-5#?
1 Answer
Aug 22, 2016
#y=2(x+2)^2-13#
Explanation:
Given -
#y=2x^2+8x-5#
Find the vertex
#x=(-b)/(2a)=(-8)/(2xx 2)=(-8)/4=-2#
At
#y=2(-2)^2+8(-2)-5=8-16-5=-13#
Quadratic equation in vertex form is -
#y=a(x-h)^2+k#
Where -
#a=2#
#h=-2#
#k=-13#
Plug in the values
#y=2(x+2)^2-13#
