How do you find the indefinite integral of #int (-2x^-3+10x^-5) dx#?

1 Answer
Aug 24, 2016

#1/x^2-5/(2x^4)+c#

Explanation:

integrate each term using the #color(blue)"power rule for integration"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(int(ax^n)dx=a/(n+1)x^(n+1))color(white)(a/a)|)))#

#rArr(-2)/(-2)x^-2+10/(-4)x^-4+c#

#rArrint(-2x^-3+10x^-5)dx=1/x^2-5/(2x^4)+c#