How do you find the indefinite integral of #int (-2x^-3+10x^-5) dx#?
1 Answer
Aug 24, 2016
Explanation:
integrate each term using the
#color(blue)"power rule for integration"#
#color(red)(|bar(ul(color(white)(a/a)color(black)(int(ax^n)dx=a/(n+1)x^(n+1))color(white)(a/a)|)))#
#rArr(-2)/(-2)x^-2+10/(-4)x^-4+c#
#rArrint(-2x^-3+10x^-5)dx=1/x^2-5/(2x^4)+c#