Question

How do you find the indefinite integral of `int -3 dx`?

Answer 1

Knowing that `intx^ndx=x^(n+1)/(n+1), n!=-1`,

`int-3dx=-3intx^0dx=-3*x^(0+1)/(0+1)=-3x+C`.

Answer 2

`-3/2x^2+c`

Explanation:

Use the `color(blue)"power rule for integration"`

`color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(int(ax^n)dx=a/(n+1) x^(n+1))color(white)(a/a)|)))`

`rArrint(-3x)dx=(-3)/(2)x^2+c=-3/2x^2+c`

c- constant of integration.