How do you write an equation of a line going through (1,7) parallel to the x-axis?

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Answer 1 · 2016-09-07T00:19:40

#y = 7#

The equation of the x-axis is #y = 0#, or #y = 0x + 0#. The slope is therefore #0#.

We want the equation of a line parallel to this one. Parallel lines mean equal slopes, so by point-slope form we have:

#y - y_1 = m(x - x_1)#

#y - 7 = 0(x - 1)#

#y - 7 = 0x - 0#

#y = 7#

Hence, the equation of the line is #y = 7#.

Hopefully this helps!

Answer 2 · 2016-09-07T10:25:28

#y = 7#

The x-axis is a horizontal line. It has a slope of 0.

Any line parallel to the x-axis is therefore also horizontal and has a slope = 0.

The equation of any horizontal line is # y = "a number"#

The number is the y-intercept, and it stays the same, regardless of which value of x is used.

The point #(1,7) means that the y-value is 7, the line will also go through 7 on the y-axis, therefore this gives us the y -intercept,

Now we have: #m = 0 and c=7#

#y =7#