Question #5b125

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Answer 1 · 2016-09-09T12:49:24

#"LPG contains 60% propane and 40% butane "#

#:."10L LPG contains 6L propane and 4L butane "#

The balanced equations of the gaseous combustion reactions

#C_3H_8(g)+5O_2(g) -> 3CO_2(g)+4H_2O(g).....(1)#

#2C_4H_10(g)+13O_2(g)-> 8CO_2(g)+10H_2O(g)......*2)#

By equation(1)

1L Propane on combustion produces 3L #CO_2(g)#

#"6L Propane on combustion produces "(3xx6)=18L" " CO_2(g)#

By equation(2)

2L Butane on combustion produces 8L #CO_2(g)#

#"4L Butane on combustion produces "(8xx4)/2=16L" " CO_2(g)#

So the total volume of #CO_2(g)# added on combustion of 10 L LPG will be (18+16)=34L