Question

How do you perform the operation in trigonometric form `(2(cos120+isin120))/(4(cos40+isin40))`?

Answer 1

`=(1/2)*(cos80+isin80)`

Explanation:

`f(x)=(1/2)*((cos120+isin120)(cos40-isin40))/((cos40+isin40)(cos40-isin40)`

`=(1/2)*(cos120cos40-i^2sin120cos40+icos40sin120-isin40cos120)/((cos40)^2-i^2(sin40)^2`

`=(1/2)*(cos80+isin80)`