How do you find the indefinite integral of int (3x^-2-4x^-3)dx?

1 Answer
Sep 21, 2016

-3/x + 2/x^2 + C

Explanation:

int (3x^-2-4x^-3)dx = 3intx^-2dx - 4intx^-3dx=

=3 x^(-2+1)/(-2+1) -4 x^(-3+1)/(-3+1) + C =

= 3 x^-1/-1 - 4 x^-2/-2 + C = -3/x + 2/x^2 + C