How do you find the indefinite integral of int (3x^-2-4x^-3)dx? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Sasha P. ยท mason m Sep 21, 2016 -3/x + 2/x^2 + C Explanation: int (3x^-2-4x^-3)dx = 3intx^-2dx - 4intx^-3dx= =3 x^(-2+1)/(-2+1) -4 x^(-3+1)/(-3+1) + C = = 3 x^-1/-1 - 4 x^-2/-2 + C = -3/x + 2/x^2 + C Answer link Related questions How do you evaluate the integral intx^3+4x^2+5 dx? How do you evaluate the integral int(1+x)^2 dx? How do you evaluate the integral int8x+3 dx? How do you evaluate the integral intx^10-6x^5+2x^3 dx? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of |x|? What is the integral of 3x? What is the integral of 4x^3? What is the integral of sqrt(1-x^2)? See all questions in Integrals of Polynomial functions Impact of this question 9004 views around the world You can reuse this answer Creative Commons License