How do you solve #4/(x+2)>2#?

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Answer 1 · 2016-09-23T21:06:31

#0>x#

We can rearrange this equation by treated the #># sign with
the #=# sign

First we times both sides by #x+2#

#4/(x+2) > 2 to#

#4>2(x+2)#

When the bracket is multiplied out we get the equation;

#4>2x + 4#

Then we take #4# from both sides

#0>2x#

Finally we divide both sides by #2#

#0>x#