A triangle has sides A, B, and C. Sides A and B have lengths of 3 and 5, respectively. The angle between A and C is $(7pi)/24$ and the angle between B and C is $(17pi)/24$ . What is the area of the triangle?

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Answer 1 · 2016-10-11T11:17:18

No such triangle is possible.
As a degenerate form the triangle would have an area of $0$

The sum of the 3 interior angles must add up to $pi$ (radians)

$/_A:C +/_B:C = (7pi)/24+(17pi)/24=(24pi)/24=pi$

$rarr/_A:B=0$

A triangle has sides A, B, and C. Sides A and B have lengths of 3 and 5, respectively. The angle between A and C is (7pi)/24(7pi)/24 and the angle between B and C is (17pi)/24 (17pi)/24. What is the area of the triangle?