Question

A charge of `4 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `37 J` to `7 J`, what is the voltage between points A and B?

Answer 1

`- 15/2 V`

Explanation:

The potential energy `U` is related to potential or voltage `V` by

`U = V q`

So `Delta V = (Delta U)/q = -30/4 = - 15/2 V`