How do you find the exact values of #sin^-1(1/2)#?

1 Answer
Oct 15, 2016

#sin^-1(1/2)=pi/6#

Explanation:

Find #sin^-1(1/2)#

This problem is asking for the ANGLE with a sine of #1/2#.

The range of #sin^-1# or #arcsin# is between #pi/2# and #-pi/2#.

If you are finding #sin^-1# of a positive value, the answer will be between 0 and #pi/2#, or the first quadrant in the unit circle. Do NOT use the second quadrant angle with a sine of #1/2#, because it does not fall within the range of #sin^-1#.

Using the unit circle, the angle with a sine of #1/2# in the first quadrant is #pi/6#.