Question

How do you solve `5x<=2-3x^2`?

Answer 1

`-2<=x<=1/3`

Explanation:

`5x<=2-3x^2`
Rearranging
`3x^2+5x-2<=0`
`(3x-1)(x+2)<=0`
`x=1/3 or x=-2`
`-2<=x<=1/3`
Checking, let `x=-1`
`-4*1=-4` which `<=0`