Question

Question #2cd41

Answer 1

The generation of calcium sulfite removes 7550 mol of `"SO"_2`.

Explanation:

First, we write a balanced equation:

`"CaO" color(white)(l)+" SO"_2 → "CaSO"_3`

Let's convert 1 ton to metric units.

`"1 ton" = 2000 color(red)(cancel(color(black)("lb"))) × (1 color(red)(cancel(color(black)("kg"))))/(2.205 color(red)(cancel(color(black)("lb")))) × "1 t"/(1000 color(red)(cancel(color(black)("kg")))) = "0.9070 t"`

`"Mass of CaSO"_3 = 0.9070 color(red)(cancel(color(black)("t CaSO"_3))) × ("1000 kg CaSO"_3)/(1 color(red)(cancel(color(black)("t CaSO"_3)))) = "907.0 kg CaSO"_3`

`"Moles of CaSO"_3 = 907.0 color(red)(cancel(color(black)("kg CaSO"_3))) × ("1000 mol CaSO"_3)/(120.14 color(red)(cancel(color(black)("kg CaSO"_3)))) = "7550 mol CaSO"_3`

`"Moles of SO"_2 = color(red)(cancel(color(black)("7550 mol CaSO"_3))) ×(1 "mol SO"_2)/(1 color(red)(cancel(color(black)("mol CaSO"_3)))) = "7550 mol SO"_2`