A triangle has sides A, B, and C. Sides A and B have lengths of 6 and 14, respectively. The angle between A and C is #(17pi)/24# and the angle between B and C is # (pi)24#. What is the area of the triangle?

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Answer 1 · 2016-11-04T21:07:57

#1/2*6*14*sin(pi/4)=21root(2)2#

The angle between A and B is given by #theta=pi-17pi/24-pi/24=(24pi-18pi)/24=pi/4#

The area is given by #1/2*A*B*sin(theta)#