How do you find the vertex and the intercepts for #y=2x^2 + 2x + 1#?
1 Answer
Nov 7, 2016
Vertex is at
y intercept is at
Explanation:
To find the vertex , first complete the square:
Now we know the horizontal, vertical, and dilation of
The vertex is at (-1/2,1/2).
Y-intercepts: Plug in zero for x, get 1
X-intercepts: solve for x using the vertex form by setting y equal to 0:
This function does not have any x intercepts. Its vertex lies above the axis and it is a positive parabola.
graph{2x^2+2x+1 [-8.23, 7.57, -1.61, 6.29]}