How do you find the exact value of #Sin(arcsin(4/5)+arctan(12/5))#?

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Answer 1 · 2016-11-08T04:03:47

#Sin(arcsin(4/5)+arctan(12/5))#

#=Sin(arcsin(4/5)+arc cot(5/12))#

#=Sin(arcsin(4/5)+arc csc(sqrt(1+(5/12)^2)#

#=Sin(arcsin(4/5)+arc csc(13/12))#

#=Sin(arcsin(4/5)+arc sin(12/13))#

#=Sin(arcsin((4/5)xxsqrt(1-(12/13)^2)+(12/13)xxsqrt(1-(4/5)^2))#

#=(4/5xx5/13)+(12/13xx3/5)=56/65#