Question

How do you find the derivative of `x^2 y^2 + sin y = 4`?

Answer 1

`2xy^2 + 2yx^2(dy/dx) + cosy(dy/dx) = 0`

`2yx^2(dy/dx) + cosy(dy/dx) = 0- 2xy^2`

`dy/dx(2yx^2 + cosy) = - 2xy^2`

`dy/dx= - (2xy^2)/(2yx^2 + cosy)`

Hopefully this helps!