How do you solve -3(6x-4)=5x+28?

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Answer 1 · 2016-11-22T21:19:53

#x = (-16)/23#

Step 1) Expand the terms within parenthesis:

#-18x + 12 = 5x + 28#

Step 2) Add #18x# to each side of the equation:

#-18x + 12 + 18x = 5x + 28 + 18x#

#12 = 23x + 28#

Step 3) Subtract 28 from each side of the equation:

#12 - 28 = 23x + 28 - 28#

#-16 = 23x#

Step 4) Divide each side of the equation by 23:

#(-16)/23 = (23x)/23#

#x = (-16)/23#