Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve $\sqrt{a - 5} \leq 4$ $sqrt(a-5)<=4$ ?

1 Answer

Nov 23, 2016

$a \leq 21$ $a le 21$

Explanation:

Square both sides to begin isolating $a$ $a$ .

$a - 5 \leq 4^{2}$ $a-5 le 4^2$

Now add $5$ $5$ to both sides.

$a \leq 16 + 5$ $a le 16+5$

Combine like terms.

$a \leq 21$ $a le 21$

There you go!

Related questions

What are common mistakes students make when solving polynomial inequalities?
How do I solve a polynomial inequality?
How do I solve the polynomial inequality $- 2 (m - 3) < 5 (m + 1) - 12$ $-2(m-3)<5(m+1)-12$ ?
How do I solve the polynomial inequality $- 6 \leq 2 (x - 5) < 7$ $-6<=2(x-5)<7$ ?
How do I solve the polynomial inequality $1 < 2 x + 3 < 11$ $1<2x+3<11$ ?
How do I solve the polynomial inequality $- 12 < - 2 (x + 1) \leq 18$ $-12<-2(x+1)<=18$ ?
How do you solve the inequality $6 x^{2} - 5 x > 6$ $6x^2-5x>6$ ?
How do you solve $x^{2} - 4 x - 21 \leq 0$ $x^2 - 4x - 21<=0$ A) [-3, 7] B) (-∞, -3] C) (-∞, -3] [7, ∞) D) [7, ∞)?
How do you solve quadratic inequality, graph, and write in interval notation $x^{2} - 8 x + 15 > 0$ $x^2 - 8x + 15 >0$ ?
How do you solve $- x^{2} - x + 6 < 0$ $-x^2 - x + 6 < 0$ ?

See all questions in Polynomial Inequalities

Impact of this question

1526 views around the world

You can reuse this answer
Creative Commons License