Question

How do you find the indefinite integral of `int -24x^5 dx`?

Answer 1

`int-24x^5dx=-4x^6+C`

Explanation:

Use the rule `intaf(x)dx=aintf(x)dx` to move the constant out of the integral.

`int-24x^5dx=-24intx^5dx`

Now use this integral rule, which is the opposite of the power rule for differentiation, to integrate the remaining term: `intx^ndx=x^(n+1)/(n+1)+C`

`-24intx^5dx=-24(x^(5+1)/(5+1))+C=-24/6x^6+C=-4x^6+C`