How do you solve #2(x+1)=0#?

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Answer 1 · 2016-12-01T16:26:52

#x = -1#

Step 1) Expand the term in parenthesis:

#2*x + 2*1 = 0#

2x + 2 = 0#

Step 2) Subtract #2# from each side of the equation to isolate the #x# term and keep the equation balanced:

#2x + 2 - 2 = 0 - 2#

#2x + 0 = -2#

#2x = -2#

Step 3) Divide each side by #2# to solve for #x# while keeping the equation balanced:

#(2x)/2 = (-2)/2#

#(cancel(2)x)/cancel(2) = -1#

#x = -1#