How do you factor out the coefficient of the variable given 2b+8?

1 Answer
Dec 2, 2016

See below

Explanation:

This is hypothetical as I am not clear on what exactly the question gives you.


Version one: equation is equal to 0

  • Given equation 2b+8 that equals zero, 2b+8=0
  • Isolate the 2b by subtracting 8 from each side 2b\cancel(+8)\cancel(\color(red)(-8))=0\color(red)(-8)\rarr2b=-8
  • Divide both sides by 2 to isolate b (\cancel(2b) )/(\cancel(\color(seagreen)(2)))=(-8)/(\color(seagreen)(2))\rarrb=-8\div2=-4

Version two: no quantity equivalence

  • GIven function 2b+8 we can apply the Distributive Property
  • convert to proper form 2b+8\rArr2(b)+2(z) where 2z=8
  • To get variable z\rArr8\div2=z=4, therefore you have 2(b)+2(4) or in factored form, 2(b+4)