Question

How do you find the area of `triangle ABC` given b=3, c=9, sinA=1/4?

Answer 1

3.375 square units

Explanation:

`Area (triangle ABC) = 1/2 bc sin A`

= `1/2 * 3 * 9 * 1/4`

= `27/8`

=`3 3/8` or `3.375`

`A (triangle ABC`)= `3.375` square units