Question

How do you solve `x(x-3)^2>=0`?

Answer 1

The answer is `x in [0, +oo[`

Explanation:

Let `f(x)=x(x-3)^2`

The domain of `f(x)` is `D_f(x)=RR`

and `(x-3)^2>=0`, `AA x in RR`

So, the sign of `f(x)` depends on the sign of `x`

Therefore, `f(x)>=0`, when `x in [0, +oo[`