Question

How do you write an equation of a circle with center at (-8,8), d=16?

Answer 1

`(x+8)^2+(y-8)^2=64`

Explanation:

The standard form of the equation of a circle is.

`color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y=b)^2=r^2)color(white)(2/2)|)))`
where (a ,b) are the coordinates of the centre and r, the radius.

`"here " a=-8,b=8" and " r=16/2=8`

substituting these values into the equation.

`(x-(-8))^2+(y-8)^2=8^2`

`rArr(x+8)^2+(y-8)^2=64" is the equation of the circle"`