Question

How do you find the values of `theta` given `cottheta=sqrt3/3`?

Answer 1

`pi/6 + kpi`

Explanation:

`cot t = 1/(tan t) = sqrt3/3`
`tan t = 3/sqrt3 = sqrt3`
Trig table and unit circle -->
`tan t = sqrt3` --> `t = pi/6` and `t = pi/6 + pi = (7pi)/6`
General answers:
`t = pi/6 + kpi`