How do you write an equation of a line with slope -15/11 and y intercept (0,-9)#?

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Answer 1 · 2016-12-26T14:37:27

$y = - \frac{15}{11} x - 9$ $y = -15/11x - 9$

To write this equation we will use the slope-intercept formula.

The slope-intercept form of a linear equation is:

$y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

In this problem we are give:

$m = - \frac{15}{11}$ $color(red)(m) = -15/11$

and

$b = - 9$ $color(blue)(b) = -9$

Substituting these into the formula gives:

$y = - \frac{15}{11} x + - 9$ $y = color(red)(-15/11)x + color(blue)(-9)$

$y = - \frac{15}{11} x - 9$ $y = color(red)(-15/11)x - color(blue)(9)$