How do you evaluate #sin^-1(-1/sqrt2)# without a calculator?

1 Answer
Dec 27, 2016

Please see the explanation.

Explanation:

Let's rationalize the denominator by multiplying the argument by 1 in the form of #sqrt(2)/sqrt(2)#:

#theta = sin^-1(-1/sqrt(2)sqrt(2)/sqrt(2))#

The denominator becomes 2 and the two numerators are multiplied:

#theta = sin^-1(-sqrt(2)/2)#

#sqrt(2)/2# is a well know value for the sine and the cosine. It is the point where they are equal to each other for the same value of #theta#; that value is #theta = pi/4# but, because of the negative sign, the angle must be in either the 3rd or the 4th quadrant.

To make it the 3rd quadrant add #pi# to #pi/4#

#theta = pi + pi/4#

#theta = (5pi)/4#

To make it the 4th quadrant subtract #pi/4# from #2pi#:

#theta = 2pi - pi/4#

#theta = (7pi)/4#