How do you solve #3x-3=6x+1#?
1 Answer
Dec 30, 2016
Explanation:
If we collect the terms in x on the left side of the equation and numeric values on the right side.
subtract 6x from both sides.
#3x-6x-3=cancel(6x)cancel(-6x)+1#
#rArr-3x-3=1# add 3 to both sides.
#-3xcancel(-3)cancel(+3)=1+3#
#rArr-3x=4# To solve for x, divide both sides by - 3
#(cancel(-3) x)/cancel(-3)=4/(-3)#
#rArrx=-4/3" is the solution"#
