How do you solve #(x-4)(x+3)<0# using a sign chart?
1 Answer
Explanation:
Find the critical points. Equate the "factors" to 0 to get the critical points. Use 0 as a critical point also.
The critical points are
Now, pick a number that lies in each region (in-between/on either side of these critical points), plug it into each factor, and find the sign of each factor in each region. You'll make a table like this one.
The last row is just the product of the two rows above it.
Also, since we manually added 0 as a critical point, we calculate
#(0-4)(0+3)" "=" "("-"4)(3)" "=" ""-"12" "<" "0#
Based on this and the chart above,