The equation of a line is #y=mx+1#. How do you find the value of the gradient m given that #P(3,7)# lies on the line?
1 Answer
Explanation:
The problem tells you that the equation of a given line in slope-intercept form is
#y = m * x + 1#
The first thing to notice here is that you can find a second point that lies on this line by making
As you know, the value of
#y = m * 0 + 1#
#y = 1#
This means that the point
#m = (Deltay)/(Deltax)#
Using
#{(Deltay = 7 - 1 = 6), (Deltax = 3 - 0 = 3) :}#
This means that the slope of the line is equal to
#m = 6/3 = 2#
The equation of the line in slope-intercept form will be
#y = 2 * x + 1#
graph{2x + 1 [-1.073, 4.402, -0.985, 1.753]}