How do you integrate #int root3(x^2)dx#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Roy E. Jan 27, 2017 By the Power Law: #3/4x^(4/3)# Explanation: #root3(x^2)=x^(1/3)#. Hence using the Power Law (#int x^n dx=1/(n+1)x^(n+1)+c, n!=0#) you get #1/(1/3+1)x^(1/3+1)+c# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 6759 views around the world You can reuse this answer Creative Commons License