How do you write the slope intercept form of the line $6 x + 5 y = - 15$ $6x+5y=-15$ ?

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Answer 1 · 2017-01-27T23:31:39

$y = - \frac{6}{5} x - 3$ $y = color(red)(-6/5)x - color(blue)(3)$

The slope-intercept form of a linear equation is:

$y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

We need to solve this equation for $y$ $y$ :

$6 x + 5 y = - 15$ $6x + 5y = -15$

$6 x - 6 x + 5 y = - 6 x - 15$ $6x - color(red)(6x) + 5y = - color(red)(6x) - 15$

$0 + 5 y = - 6 x - 15$ $0 + 5y = -6x - 15$

$5 y = - 6 x - 15$ $5y = -6x - 15$

$\frac{5 y}{5} = \frac{- 6 x - 15}{5}$ $(5y)/color(red)(5) = (-6x - 15)/color(red)(5)$

$(color(red)(cancel(color(black)(5)))y)/cancel(color(red)(5)) = (-6x)/5 - 15/5$

$y = -6/5x - 3$

How do you write the slope intercept form of the line 6x+5y=-156x+5y=−156x+5y=-15?