Question

Question #7738f

Answer 1

`(3,5)`

Explanation:

To graph these `color(blue)"linear equations"` we can find the
`color(blue)"x and y intercepts".`

When a line crosses the y-axis, the value of the corresponding x-coordinate is zero.
Substituting x = 0 into the equation gives us the value of the
`color(blue)"y-intercept"`

Similarly when the line crosses the x-axis, the y-coordinate is zero and substituting y = 0 into the equation gives the value of the `color(blue)"x-intercept"`

`color(blue)" equation :" x-y=-2`

`x=0to0-y=-2toy=2larrcolor(red)" y-intercept"`

`y=0tox-0=-2tox=-2larrcolor(red)"x-intercept"`

Plot the points (0 ,2) and (-2 ,0) and draw a straight line through them.

`color(blue)"equation :"x+y=8`

`x=0to0+y=8toy=8larrcolor(red)"y-intercept"`

`y=0tox+0=8tox=8larrcolor(red)"x-intercept"`

On the same grid as the previous points, plot (0 ,8) and (8 ,0)

The solution to the system is at `color(blue)" the point of intersection of the 2 lines"`
graph{(y-x-2)(y+x-8)=0 [-10, 10, -5, 5]}