How do you solve sqrt(2x-7)>=5? Precalculus Solving Rational Inequalities Polynomial Inequalities 1 Answer Babette Feb 4, 2017 x>=16 Explanation: Square both sides (sqrt(2x-7))^2>=5^2 2x-7>=25 Add 7 to both sides 2x>=32 Divide both sides by 2 x>=16 Answer link Related questions What are common mistakes students make when solving polynomial inequalities? How do I solve a polynomial inequality? How do I solve the polynomial inequality -2(m-3)<5(m+1)-12? How do I solve the polynomial inequality -6<=2(x-5)<7? How do I solve the polynomial inequality 1<2x+3<11? How do I solve the polynomial inequality -12<-2(x+1)<=18? How do you solve the inequality 6x^2-5x>6? How do you solve x^2 - 4x - 21<=0 A) [-3, 7] B) (-∞, -3] C) (-∞, -3] [7, ∞) D) [7, ∞)? How do you solve quadratic inequality, graph, and write in interval notation x^2 - 8x + 15 >0? How do you solve -x^2 - x + 6 < 0? See all questions in Polynomial Inequalities Impact of this question 1546 views around the world You can reuse this answer Creative Commons License