A solid disk with a radius of #8 m# and mass of #8 kg# is rotating on a frictionless surface. If #360 W# of power is used to increase the disk's rate of rotation, what torque is applied when the disk is rotating at #6 Hz#?
1 Answer
Feb 9, 2017
Explanation:
We are told we have a rotating spinning coin.
Step 1. Gather the information that you know and need
- Mass of disk:
#"mass"=m=8" kg"# - Radius of disk:
#"radius"=r=8" m"# - Power applied to increase rotation:
#P=360" W"# - Frequency:
#f=6" Hz"# - Torque required: ??
Step 2. Determine the formula using the above givens
#P# is the power applied,#P=tau omega# - Therefore, the formula for torque is
#tau=P"/"omega# - Angular speed,
#omega=f*2pi=6*2pi=12pi#
Step 3. Plug your answer into the formula for torque
